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Factorization — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSFactorization1 Mark
MCQ
The factorisation of $\text{x}^2+\text{x}+\frac{1}{4}$ is:
  • A
    $(\frac{\text{x}}{2}-1)^2$
  • B
    $(\frac{\text{x}}{2}+1)^2$
  • ✓
    $(\text{x}+\frac{1}{2})^2$
  • D
    $(\text{x}-\frac{1}{2})^2$
✓

Answer

Correct option: C.
$(\text{x}+\frac{1}{2})^2$
$\text{x}^2+\text{x}+\frac{1}{4}$
$=\text{x}^2+2(\text{x})(\frac{1}{2})+(\frac{1}{2})^2$
$=(\text{x}+\frac{1}{2})^2$

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