MCQ
The factorisation of $x^{2}-9$ is
- A$(x-3)^{2}$
- B$(x+3)^{2}$
- ✓$(x+3)(x-3)$
- Dnone of these
✓
Answer
Correct option: C.
$(x+3)(x-3)$
c
$x^{2}-9=(x)^{2}-(3)^{2}=(x-3)(x+3)$
$x^{2}-9=(x)^{2}-(3)^{2}=(x-3)(x+3)$
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