MCQ
The factorisation of $y^{2}-7 y+12$ is
  • A
    $(y+3)(y+4)$
  • B
    $(y+3)(y-4)$
  • C
    $(y-3)(y+4)$
  • $(y-3)(y-4)$

Answer

Correct option: D.
$(y-3)(y-4)$
d
$y^{2}-7 y+12$
$=y^{2}-3 y-4 y+12$
$=y(y-3)-4(y-3)$
$=(y-3)(y-4)$

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