MCQ
The factorisation of $y^2 - 7y + 12$ is:
  • A
    $(y + 3) (y + 4)$
  • B
    $(y + 3) (y - 4)$
  • C
    $(y - 3) (y + 4)$
  • $(y - 3) (y - 4)$

Answer

Correct option: D.
$(y - 3) (y - 4)$
$= y^2 - 7y + 12$
$= y^2 - 3y - 4y + 12$
$= y(y - 3) - 4(y - 3)$
$= (y - 3) (y - 4)$

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