MCQ
The factorisation of $z^2 - 4z - 12$ is:
- A$(z + 6) (z + 2)$
- B$(z - 6) (z - 2)$
- ✓$(z - 6) (z + 2)$
- D$(z + 6) (z - 2)$
✓
Answer
Correct option: C.
$(z - 6) (z + 2)$
C. $(z - 6) (z + 2)$
Solution:
$= z^3 - 4z – 12$
$= z^2 - 6z + 2z - 12$
$= z(z - 6) + 2(z - 6)$
$= (z - 6) (z + 2)$
Solution:
$= z^3 - 4z – 12$
$= z^2 - 6z + 2z - 12$
$= z(z - 6) + 2(z - 6)$
$= (z - 6) (z + 2)$
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