MCQ
The factorisation of$x^{2}+x+x y+y+z x+z$ is
- ✓$(x+y+z)(x+1)$
- B$(x+y+z)(x+y)$
- C$(x+y+z)(y+z)$
- D$(x+y+z)(z+x)$
✓
Answer
Correct option: A.
$(x+y+z)(x+1)$
a
$x^{2}+x+x y+y+z x+z$
$=x(x+1)+y(x+1)+z(x+1)$
$=(x+1)(x+y+z)$
$x^{2}+x+x y+y+z x+z$
$=x(x+1)+y(x+1)+z(x+1)$
$=(x+1)(x+y+z)$
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