The feasible region is : - Vidyadip

Question

The feasible region is :

✓

Answer

(C) always convex polygon

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

If the area bounded by the curve $2 x^2+y^2=2$ is $A$. Then which of the following is the value of $A$ ?

A bag contains 5 red and 3 blue balls. If 3 balls are drawn at random without replacement, then the probability that exactly two of the three balls were red, the first ball being red, is

If two events are independent, then

If area bounded by the curves $x = at^2$ and $y = ax^2$ is $1,$ then a $.........$

If $\sin^{-1}\text{x}-\cos^{-1}\text{x}=\frac{\pi}{6},$ then x =

$\frac{1}{2}$
$\frac{\sqrt3}{2}$
$-\frac{1}{2}$
$\text{none of these}$

The plane x + y = 0:

Is parallel to z-axis
Is perpendicular to z-axis
Passes through z-axis
None of these

The corner points of the feasible region determined by the system of linear constraints are (0, 10), (5, 5), (15, 15), (0, 20). Let z = px + qy where p, q > 0. Condition on p and q so that the maximum of z occurs at both the points (15, 15) and (0, 20) is __________.

q = 2p
p = 2p
p = q
q = 3p

Let $\text{f(x)}=\begin{cases}\frac{1}{|\text{x}|} & \text{for |x|}\geq1\\\text{ax}^2+\text{b} & \text{for |x|}<1\end{cases}$ if f(x) is continuous and differentiable at any point, then:

$\text{a}=\frac{1}{2},\text{b}=-\frac{3}{2}$
$\text{a}=-\frac{1}{2},\text{b}=\frac{3}{2}$
$\text{a}=1,\text{b}=-1$
None of these.

If vectors $(\text{x}-2)\ \vec{\text{a}}+\vec{\text{b}}$ and $(2\text{x}+1)\ \vec{\text{a}}-\vec{\text{b}}$ are parallel then x:

$\frac{1}{3}$
$3$
$-3$
$\frac{-1}{3}$

What is the value of $\int_{\frac{\pi}{6}}^{\frac{\pi}{3}}\frac{\text{dx}}{\sin2\text{x}}?$

$\frac{1}{2}\log(-1)$
$\log(-1)$
$\log3$
$\log\sqrt{3}$