MCQ
The feasible solution for a $LPP$ is shown in Figure Let $z=3 x-4 y$ be the objective function. Maximum of $Z$ occurs at $......$
  • $(5,0)$
  • B
    $(6,5)$
  • C
    $(6,8)$
  • D
    $(4,10)$

Answer

Correct option: A.
$(5,0)$
a
Corner point

Objective function

$z=3 x-4 y$

$(0,0)$ $z=3(0)-4(0)=0$
$(5,0)$ $z=3(5)-4(0)=15$ (Maximum value)
$(6,5)$ $z=3(6)-4(5)=18-20=-2$
$(6,8)$ $z=3(6)-4(8)=-14$
$(4,10)$ $z=3(4)-4(10)=-28$
$(0,8)$ $z=3(0)-4(8)=-32($ minimum value )

maximum value of objective function $z=3 x-4 y$ is $15$ which exists at point $(5,0).$

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