MCQ
The feasible solution for a LPP is shown in Figure Let $z=3 x-4 y$ be the objective function. (Maximum value of $z+$ Minimum value of $z$ ) is equal to $....$
  • A
    $13$
  • B
    $01$
  • C
    $-13$
  • $-17$

Answer

Correct option: D.
$-17$
d
Corner point

Objective function

$z=3 x-4 y$

$(0,0)$ $z=3(0)-4(0)=0$
$(5,0)$ $z=3(5)-4(0)=15$ (Maximum value)
$(6,5)$ $z=3(6)-4(5)=18-20=-2$
$(6,8)$ $z=3(6)-4(8)=-14$
$(4,10)$ $z=3(4)-4(10)=-28$
$(0,8)$ $z=3(0)-4(8)=-32($ minimum value )

we have (Maximum value of $z$ ) $+$ (Minimum value of $z$ ) $=15-32=-17$.

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