MCQ
The figure shows a velocity-time graph of a particle moving along a straight line If the particle starts from the position $x_0=-15\,m$ , then its position at $t=2\,s$ will be ........ $m$


- ✓$-5$
- B$5 $
- C$10$
- D$15 $

$x-x_{0}=\frac{1}{2} \times 2 \times 10$
$x-(-15)=10 \Rightarrow x=-5 m$
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