
- A

- B

- C

- ✓








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$STATEMENT-2$: The $\mathrm{Fe}$ in $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}_3 \mathrm{SO}_4\right.$ has three unpaired electrons.


Product $(B)$ is
$(i)$ Glucose $+ ROH \quad \stackrel{\text { dry } HCl }{\longrightarrow}$ Acetal
$\xrightarrow[{{{\left( {C{H_3}CO} \right)}_2}O}]{{x\,eq.of}}$ acetyl derivative
$(ii)$ Glucose $\xrightarrow{{Ni/{H_2}}}A\xrightarrow[{{{\left( {C{H_3}CO} \right)}_2}O}]{{y\,\,eq.\,of}}$ acetyl derivative.
$(iii)$ Glucose $\xrightarrow[{{{\left( {C{H_3}CO} \right)}_2}O}]{{z\,ed.\,of}}$ acetyl derivative.
$' x ^{\prime},{ }^{\prime} y ^{\prime}$ and ${ }^{\prime} z^{\prime}$ in these reactions are respectively.