Question
The first ionisation potential is maximum for
It is due to the more stable (half-filled orbitals) configurations of $N$.
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$(1)$ It has $2$ angular nodes
$(2)$ It has $3$ radial nodes
$(3)$ It is a 4d state
$(4)$ The nuclear charge experienced by the electron in this state is less than $2 e$, where $e$ is the magnitude of the electronic charge.
Given $\mathrm{R}=8.31\, \mathrm{~J} \,\mathrm{~K}^{-1} \,\mathrm{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19$ $\left.10^{-4.79}=1.62 \times 10^{-5}\right]$


