- ✓$Na < Mg > Al < Si$
- B$Na > Mg > Al > Si$
- C$Na < Mg < Al < Si$
- D$Na > Mg > Al < Si$
For $A l\left(3 s^{2} 3 p^{1}\right)$, electron has to be removed from partially filled $3 p$ orbital whereas in $M g\left(3 s^{2}\right)$, electron has to be removed from stable fully filled $3 s$ orbital.
Removal of an electron from stable, fully filled orbital requires more energy than removal of electron from partially filled orbital.
Thus, ionisation enthalpy for $M g$ is greater than ionisation enthalpy for $A l$.
So, the correct order of first ionization enthalpies is: $N a
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$\mathrm{A}+\mathrm{B} \rightleftharpoons 2 \mathrm{C}$
the value of equilibrium constant is $100$ at $298\, \mathrm{~K}$. If the initial concentration of all the three species is $1\, \mathrm{M}$ each, then the equilibrium concentration of $\mathrm{C}$ is $\mathrm{X} \times 10^{-1} \,\mathrm{M}$. The value of $\mathrm{x}$ is $.....$ (Nearest integer)