Li Be BC N O F Nel In a period from left to right, ionization potential increases. But in case of nitrogen
and oxygen, nitrogen has more ionization potential than oxygen atom due to stable electronic configuration of nitrogen. $7 N=1 s^{2}, 2 s^{2} 2 p^{3} \mid$
$\uparrow\|\| \|$
(Stable configuration) $80=1 s^{2}, 2 s^{2} 2 p^{4}$ (Unstable configuration) Nitrogen has stable configuration as
the p-orbitals are half-filled completely. So, more energy is required to remove an electron from the outermost orbit of nitrogen atom. So, $\mathrm{N}_{2}$, has 14.5 value of ionisation potential.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - C = CH}
\end{array}\xrightarrow[{{H_2}O}]{{HgS{O_4},{H_2}S{O_4}}}X$ $\xrightarrow[{(ii)\,conc.{H_2}S{O_4}/\Delta }]{{(i)\,{C_2}{H_5}MgBr,{H_2}O}}Y$
$\mathrm{x}=$ . . . . . . . . . (Nearest integer)
Given : $\left(\mathrm{K}_{\mathrm{r}}\right)_{\text {water }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$.
density of acetic acid is $1.2 \mathrm{~g} \mathrm{~mol}^{-1}$
molar mass of water $=18 \mathrm{~g} \mathrm{~mol}^{-1}$.
molar mass of acetic acid $=60 \mathrm{~g} \mathrm{~mol}^{-1}$.
density of water $=1 \mathrm{~g} \mathrm{~cm}^{-3}$
Acetic acid dissociates as
$\mathrm{CH}_3 \mathrm{COOH} \rightleftharpoons \mathrm{CH}_3 \mathrm{COO}^{\oplus}+\mathrm{H}^{\oplus}$
$(A)\, F^-, Na^+, Mg^{+2}$ $(B) \,Ni, Cu, Zn$
$(C)\, N^{-3}, Cs^+, H^-$ $(D)\, Li, He, Be^{+2}$