The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is $20 \,cm$. The length of the open organ pipe is........$cm$.
JEE MAIN 2022, Medium
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$f _{1}=\frac{2 v }{2 l _{1}}$
$f _{2}=\frac{ v }{41_{2}}$
$f _{1}= f _{2}$
$=\frac{2 v }{2 l _{1}}=\frac{ v }{41_{2}}$
$1_{1}=41_{2}=80 \,cm$
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