The first step in formulating an LP problem is: - Vidyadip

MCQ

The first step in formulating an LP problem is:

A
Graph the problem.
B
Perform a sensitivity analysis.
C
Define the decision variables.
D
Understand the managerial problem being faced.

✓

Answer

Understand the managerial problem being faced.

Solution:

The first step in formulating an linear programming problem is to understand the managerial problem being faced i.e., determine the quantities that are needed to solve the problem.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The vector$(s)$ which is/are coplanar with vectors $\hat{i}+\hat{j}+2 \hat{k}$ and $\hat{i}+2 \hat{j}+\hat{k}$, and perpendicular to the vector $\hat{i}+\hat{j}+\hat{k}$ is/are

$(A)$ $\hat{j}-\hat{k}$ $(B)$ $-\hat{i}+\hat{j}$ $(C)$ $\hat{i}-\hat{j}$ $(D)$ $-\hat{j}+\hat{k}$

Area of the region bounded by the curve $\text{y}=\sqrt{49-\text{x}^2}$ and the x - axis is:

$\frac{49}{2}\pi\text{ sq}\text{ units}$
$98\pi\text{ sq}\text{ units}$
$49\pi\text{ sq}\text{ units}$
$240\pi\text{ sq}\text{ units}$

Let A is a square matrix of order n and a being a scalar then ∣aA∣ =

a∣A∣
∣a∣∣A∣
aⁿ∣A∣
none of these

The value of the definite integral

$\int_{\pi / 24}^{5 \pi / 24} \frac{d x}{1+\sqrt[3]{\tan 2 x}} \text { is }$

The area of circle $x^2+y^2=4$ is

The projection of the join of the two points (1, 4, 5), (6, 7, 2) on the line whose d.ss are (4, 5, 6) is:

$\frac{17}{\sqrt{77}}$
$\frac{7}{6}$
$21$
$\frac{7}{9}$

Let $f:[1, \infty) \rightarrow[2, \infty)$ be a differentiable function such that $f(1)=2$. If $6 \int_1^x f(t) d t=3 x f(x)-x^3$ for all $x \geq 1$, then the value of $f(2)$ is

The function $f: R \rightarrow R$ defined by $f(x)=6^x+6^{|x|}$ is

The number of matrices $A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]$, where a $, b, c, d \in\{-1,0,1,2,3, \ldots \ldots, 10\}$, such that $A=A^{-1}$, is

The shortest distance between the lines $\frac{{x - 3}}{3} = \frac{{y - 8}}{{ - 1}} = \frac{{z - 3}}{1}\& \frac{{x + 3}}{{ - 3}} = \frac{{y + 7}}{2} = \frac{{z - 6}}{4}$ is