Question
The first term of an A.P. is p and its common difference is q. Find its $10^{th}$​​​​​​​ term.

Answer

Given,
First term, $a = p$
and Difference, $d = q$
We have to find $10^{th}$ term,
We knaw $a_n = a + (n - 1)d$
$\Rightarrow a_{10} = p + (10 - 1)q$
$\Rightarrow a_{10} = p + 9q$
Hence, term of given A.P. is $p + 9q.$

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