$\frac{{d\ln k}}{{dt}} = \frac{{\Delta {H^o}}}{{R{T^2}}}$
or $\ln {k_p} = - \frac{{\Delta {H^o}}}{{RT}} + I$.
Hence $(a)$ is correct $(b)$ is also correct as plot of $log\,(X)$ vs $time$ is linear.
$ (c) $ is wrong because $p \propto T$ at constant volume. $(d)$ is correct by Boyle’s law.
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$C{l_2} + 2{Y^ - } \to \,2C{l^ - }\, + \,{Y_2}$
The incorrect match regarding above reaction is
| List-$I$ (Compound) | List-$II$ (Colour) |
| $A$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O}$ | $I$ Violet |
| $B$ $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$ | $II$ Blood Red |
| $C$ $[\mathrm{Fe}(\mathrm{SCN})]^{2+}$ | $III$ Prussian Blue |
| $D$ $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3$ | $IV$ Yellow |
Choose the correct answer from the options given below :
