Download App

Linear Equations in Two Variables — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsLinear Equations in Two Variables1 Mark
MCQ
The force applied on a body is directly proportional to the acceleration produced on it. The equation to represent the above statement is:
  • A
    y = kx
  • B
    y + x = 0
  • C
    None of these
  • D
    y = x
✓

Answer

  1. y = kx
    Solution:
    Let force applied be y and acceleration produced be x. The force applied on a body is directly proportional to the acceleration produced on it.
    Yαx
    y = kx
    Where k is proportionality constant.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q" from Linear Equations in Two Variables→Linear Equations in Two Variables — all question types→Maths STD 9 question papers→Gujarat Board STD 9 question papers→Gujarat Board question paper generator→

Similar questions

(x + 1) is a factor of xn + 1 only if:
→
If $f(x-2)=2 x^2-3 x+4$, then the remainder when $f(x)$ is divided by $(x-1)$, is
→
If x + 2 and x - 1 are the factors of x3 + 10x2 + mx + n, then the values of m and n are respectively
→
The class mark of the class interval 2.4-6.6 is:
→
In a parallelogram ABCD, if $\angle\text{DAB}=75^\circ$ and $\angle\text{DBC}=60^\circ,$ then $\angle\text{BDC}=$
  1. 75°
  2. 60°
  3. 45°
  4. 55°
→
Write the correct answer in the following:
If the area of an equilateral triangle is $16\sqrt{3}\text{cm}^2,$ then the perimeter of the triangle is:
→
$2\sqrt{3}+\sqrt{3}$ is equal to :
→
The value of $\Big(\frac{\text{x}^{\text{l}}}{\text{x}^{\text{m}}}\Big)^{\frac{1}{\text{lm}}}\times\Big(\frac{\text{x}^{\text{m}}}{\text{x}^{\text{n}}}\Big)^{\frac{1}{\text{mn}}}\times\Big(\frac{\text{x}^{\text{n}}}{\text{x}^{\text{l}}}\Big)^{\frac{1}{\text{nl}}}$ is :
→
A spherical ball of radius 3cm is melted and recast into three spherical balls. The radii of two of these balls are 1.5cm and 2cm. The radius of third ball is:
  1. 1cm
  2. 1.5cm
  3. 2.5cm
  4. 0.5cm
→
The name of the horizontal line drawn to determine the position of any point in the Cartesian plane is:
→