MCQ
The formula of dichloro bis (urea) copper $(II)$  is
  • A
    $\left[ {Cu\{ O = C{{(N{H_2})}_2}\} C{l_2}} \right]$
  • $\left[ {CuC{l_2}{{\{ O = C{{(N{H_2})}_2}\} }_2}} \right]$
  • C
    $\left[ {Cu\{ O = C{{(N{H_2})}_2}\} Cl} \right]Cl$
  • D
    $\left[ {CuC{l_2}} \right]\{ O = C{(N{H_2})_2}{H_2}\} $

Answer

Correct option: B.
$\left[ {CuC{l_2}{{\{ O = C{{(N{H_2})}_2}\} }_2}} \right]$
b
In this complex, $2$ 'chloro' ligands and $2$ 'urea' ligands are present. By following alphabetical order, chloro comes first with its number (i.e., dichloro) followed by the second ligand $\left( O = C \left( NH _2\right)_2\right)_2$. Since, it is a bidentate ligand (i.e., can attach at more than one binding sites), the prefix 'bis' is used followed by the name of ligand urea. Cu oxidation state will be $+2(x-2=0)$. So, the correct answer is $\left[ CuCl _2\left( O = C \left( NH _2\right)_2\right)_2\right]$.

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