MCQ
The formula of prussian blue is:
- A$ \mathrm{Na}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] $
- B$ \mathrm{Fe}(\mathrm{CN})_2 $
- C$ \mathrm{Fe}(\mathrm{CNS})_3 $
- ✓$ \mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 $
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