MCQ
The fourth term in the expansion of $(x-2 y)^{12}$ is:
  • $-1760 x^9 \times y^3$
  • B
    $-1670 x^9 \times y^3$
  • C
    $-7160 x^9 \times y^3$
  • D
    $-1607 x^9 \times y^3$

Answer

Correct option: A.
$-1760 x^9 \times y^3$
  1. $-1760 x^9 \times y^3$
Solution:
We know that the general term of an expansion $(a+b) n$ is $T_{r+1}={ }^n C_r a^{n-r}$ br.
Now, we have to find the fourth term in the expansion $(x-2 y)^{12}$
Hence, $r=3, a=x, b=-2 y, n=12$.
Now, substitute the values in the formula, we get
$T_{3+1}={ }^{12} C_3 x^{12-3}(-2 y)^3$.
On solving this, we get
$T_4=-1760 x^9 y^3$.

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