The frequencies of two sound sources are $256 Hz$ and $260 Hz$. At $t = 0,$ the intensity of sound is maximum. Then the phase difference at the time $t = \frac{1}{16}\, sec$ will be
Medium
Download our app for free and get started
(c) Time interval between two consecutive beats
$T = \frac{1}{{{n_1} - {n_2}}} = \frac{1}{{260 - 256}} = \frac{1}{4}\sec $ so, $t = \frac{1}{{16}} = \frac{T}{4}\,\,\sec $
By using time difference =$\frac{T}{{2\pi }} \times $Phase difference
$ \Rightarrow $$\frac{T}{4} = \frac{T}{{2\pi }} \times \phi \Rightarrow \phi = \frac{\pi }{2}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A point source emits sound equally in all directions in a non-absorbing medium, Two points $P$ and $Q $ are at distance of $2m$ and $3m$ respectively from the source. The ratio of the intensities of the waves at $P$ and $ Q$ is
A composition string is made up by joining two strings of different masses per unit length $\rightarrow \mu$ and $4\mu$ . The composite string is under the same tension. A transverse wave pulse $: Y = (6 mm) \,\,sin\,\,(5t + 40x),$ where $‘t’$ is in seconds and $‘x’$ in meters, is sent along the lighter string towards the joint. The joint is at $x = 0$. The equation of the wave pulse reflected from the joint is
The beats are produced by two sound sources of same amplitude and of nearly equal frequencies. The maximum intensity of beats will be ...... that of one source
The disc of a siren containing $60$ holes rotates at a constant speed of $360\,rpm$. The emitted sound is in unison with a tuning fork of frequency .... $Hz$