during $1$ vibration of fork sound will travel $\frac{{352}}{{384}}m$
during $36$ vibration of fork sound will travel $\frac{{352}}{{384}} \times 36 = 33\,m$

${y_1} = {10^{ - 6}}\sin [100\,t + (x/50) + 0.5]m$
${y_2} = {10^{ - 6}}\cos \,[100\,t + (x/50)]m$
where $ x$ is expressed in metres and $t$ is expressed in seconds, is approximately .... $ rad$