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STD 11 - 2. structure of atom — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 2. structure of atom4 Marks
MCQ
The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies $E_1$ (lower) and $E_2$ (higher) is given by 
  • A
    $v = \frac{E_1+E_2}{h}$
  • B
    $v = \frac{E_1 - E_2}{h}$
  • C
    $v = \frac{E_1 \times E_2}{h}$
  • ✓
    $v = \frac{E_2 - E_1}{h}$
✓

Answer

Correct option: D.
$v = \frac{E_2 - E_1}{h}$
d
$\mathrm{h} v=\mathrm{E}_{2}-\mathrm{E}_{1}$

$v=\frac{E_{2}-E_{1}}{h}$

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