MCQ
The function $f$ defined by $f(x)=4 x^4-2 x+1$ is increasing for
  • A
    $x<1$
  • B
    $x>0$
  • C
    $x<\frac{1}{2}$
  • $x>\frac{1}{2}$

Answer

Correct option: D.
$x>\frac{1}{2}$
(d) : We have, $f(x)=4 x^4-2 x+1 \Rightarrow f^{\prime}(x)=16 x^3-2$
The function is increasing if $f^{\prime}(x)>0$
$
\Rightarrow 16 x^3-2>0 \Rightarrow x>\frac{1}{2}
$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Find the absolute maximum value of $f(x)=4 x-\frac{1}{2} x^2$ in interval $\left[-2, \frac{9}{2}\right]$.
If $f(x) = 4x^3 -x^2 - 2x + 1$ and $g(x) = [ \begin{array}{*{20}{c}}{Min\,\,\,\left\{ {f(t)\,\,\,\,0\,\, \le \,\,t\,\, \le \,\,x} \right\}}&{;\,\,\,\,0\,\, \le \,\,x\,\, \le \,\,1}\\{3\,\, - \,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}&{;\,\,\,\,1\,\, < \,\,x\,\, \le \,\,2}\end{array}$ then $g\left( {\frac{1}{4}} \right) + g\left( {\frac{3}{4}} \right) + g\left( {\frac{5}{4}} \right)$ has the value equal to
Let $f(x)$ be a quadratic polynomial such that $f(-2)$ $+f(3)=0$. If one of the roots of $f(x)=0$ is $-1$, then the sum of the roots of $f(x)=0$ is equal to
Let $M$  and  $m$  be respectively the local maximum and the local minimum values of the function, $f(x) = \,2{x^3} - 9{x^2} + 12x + 5$  in the interval $[0, 3].$  Then $M-m$  is equal to
If $\int {{x^5}\,{e^{ - {x^2}}}\,dx\, = \,g\,(x)\,{e^{ - {x^2}}} + \,c,} $ where $c$ is a constant of integration, then $g(-1)$ is equal to
Let $\mathrm{A}=\left[\begin{array}{ll}1 & 2 \\ 0 & 1\end{array}\right]$ and $\mathrm{B}=\mathrm{I}+\operatorname{adj}(\mathrm{A})+(\operatorname{adj} \mathrm{A})^2+\ldots+$ $(\operatorname{adj} \mathrm{A})^{10}$. Then, the sum of all the elements of the matrix $B$ is :
S is a relation over the set R of all real numbers and it is given by $(\text{a, b})\in\text{S}\Leftrightarrow\text{ab}\geq0.$ Then, S is:
  1. Symmetric and transitive only.
  2. Reflexive and symmetric only.
  3. Antisymmetric relation.
  4. An equivalence relation.
If the shortest distance between the lines $\frac{x-4}{1}=\frac{y+1}{2}=\frac{z}{-3}$ and $\frac{x-\lambda}{2}=\frac{y+1}{4}=\frac{z-2}{-5}$ is $\frac{6}{\sqrt{5}}$, then the sum of all possible values of $\lambda$ is :
If $\left(\frac{1}{2}, \frac{1}{3}, n\right)$ are the direction cosines of a line, then the value of $n$ is
Let $f(x)$ and $g(x)$ be two functions having finite non-zero $3^{rd}$ order derivatives $f'''(x)$ and $g'''(x)$ for all, $x \in R$. If $f(x)g(x) = 1$ for all $x \in R$, then ${{f'''} \over {f'}} - {{g'''} \over {g'}}$ is equal to