- ✓$(0,1)$
- B$(0,\infty)$
- C$(-1,1)$
- D$(-1,0)$
$\Rightarrow f^{\prime}(x)=\left\{\begin{array}{ll}{\frac{2}{x}-2 x} & {\text { if } x>0} \\ {\frac{2}{x}+2 x} & {\text { if } x<0}\end{array}\right.$
$\therefore f^{\prime}(x)>0$ only for $x \in(0,1)$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
If $y(\pi)=\pi+2$, then the value of $y\left(\frac{\pi}{2}\right)$ is:
($A$) $\mathrm{M}$ is invertible
($B$) There exists a nonzero column matrix $\left(\begin{array}{l}a_1 \\ a_2 \\ a_3\end{array}\right)$ such that $M\left(\begin{array}{l}a_1 \\ a_2 \\ a_3\end{array}\right)=\left(\begin{array}{l}-a_1 \\ -a_2 \\ -a_3\end{array}\right)$
($C$) The set $\left\{\mathrm{X} \in \mathbb{R}^3: \mathrm{MX}=\mathbf{0} \neq \neq 0\right\}$, where $\mathbf{0}=\left(\begin{array}{l}0 \\ 0 \\ 0\end{array}\right)$
($D$) The matrix $(M-2 I)$ is invertible, where $I$ is the $3 \times 3$ identity matrix
Statement $-2:$ The functions $x^2e^x$ and $x^2e^{-x}$ are increasing for all $x > 0$ and the sum of two increasing functions in any interval $(a, b)$ is an increasing function in $(a, b).$