Question
The function f(x) = cot x is discontinuous on the set

Answer

(d) $\{x=n \pi: n \in Z \}$
Explanation:  We have $f ( x )=\cot x$ is continuous in $R-\{n \pi: n \in Z\}$
Since, $f ( x )=\cot x=\frac{\cos x}{\sin x}$ (since, $\sin x =0$ at $n \pi, n \in Z$ )
Hence, $f ( x )=\cot x$ is discontinuous on the set $\{x=n \pi: n \in Z\}$

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