Question
The function $f(x)=\frac{4-x^2}{4 x-x^3}$ is

Answer

(c) : $f(x)=\frac{4-x^2}{4 x-x^3}=\frac{4-x^2}{x(2-x)(2+x)}$
So, $f(x)$ is discontinuous at $x=0,2,-2$.

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