MCQ
The function $f(x) = \frac{{\log (1 + ax) - \log (1 - bx)}}{x}$ is not defined at $x = 0$. The value which should be assigned to f at $x =0$ so that it is continuos at $x = 0$, is
- A$a - b$
- ✓$a + b$
- C$\log a + \log b$
- D$\log a - \log b$
as $x \to 0,$ therefore to be continuous at a function, its value must be
$a + b$ at $x = 0$ $ \Rightarrow \,\,f(0) = a + b.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.