MCQ
The function $f(x) = x + \sin x$ has
- AA minimum but no maximum
- BA maximum but no minimum
- ✓Neither maximum nor minimum
- DBoth maximum and minimum
Now $f'(x) = 0 \Rightarrow 1 + \cos x = 0 \Rightarrow \cos x = - 1 \Rightarrow x = \pi $
Now $f''(x) = - \sin x$,$f''(\pi ) = 0$,,
$f'''(\pi ) = 1 \ne 0$
$\therefore$ Neither maximum nor minimum.
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