MCQ
The function $f(x) = {x^{1/x}}$ is
- AIncreasing in $(1,\,\,\infty )$
- BDecreasing in $(1,\,\,\infty )$
- ✓Increasing in $(1,\,e),$ decreasing in $(e,\infty )$
- DDecreasing in $(1,\,e),$ increasing in$(e,\infty )$
==>$\frac{1}{y}\frac{{dy}}{{dx}} = \frac{1}{{{x^2}}} - \frac{{\log x}}{{{x^2}}} = \frac{{1 - \log x}}{{{x^2}}}$
==>$\frac{{dy}}{{dx}} = {x^{1/x}}\left( {\frac{{1 - \log x}}{{{x^2}}}} \right)$
Now, ${x^{1/x}} > 0$for all x and $\frac{{1 - \log x}}{{{x^2}}} > 0$ in $ (1, e) $ and
$\frac{{1 - \log x}}{{{x^2}}} < 0$ in $(e,\infty )$
$\therefore$ $f(x)$ is increasing in $ (1, e) $ and decreasing in $(e,\,\infty ).$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
