The function f(x) = x9 + 3x7 + 64 is increasing on: 1. R 2. (- ,0… - Vidyadip

Question

The function f(x) = x⁹+ 3x⁷ + 64 is increasing on:

$\text{R}$
$(-\infty,0)$
$(0,\infty)$
$\text{R}_0$

✓

Answer

$\text{R}$

Solution:

$\text{f}(\text{x})=\text{x}^9+3\text{x}^7+64$

$\text{f}'(\text{x})=9\text{x}^8+21\text{x}^6>0,\forall\ \text{x}\in\text{R}$

So, f(x) is increasing on R.

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