MCQ
The function $\sin ^2(\omega t)$ represents
  •  a simple harmonic motion with a period π/ω
  • B
    a simple harmonic motion with a period 2π/ω
  • C
    a periodic, but not simple harmonic motion with a period π/ω
  • D
    a periodic, but not simple harmonic motion with a period 2π/ω

Answer

Correct option: A.
 a simple harmonic motion with a period π/ω
a simple harmonic motion with a period π/ω
Solution :
$\sin ^2 \omega t=\frac{1}{2}(1-\cos 2 \omega t)$ This is an SHM with period $\frac{2 \pi}{2 \omega}=\frac{\pi}{\omega}$. Its equilibrium position is at $\frac{1}{2}$ instead of zero.

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