MCQ
The function$f(x) = [x]\cos \left[ {\frac{{2x - 1}}{2}} \right]\pi ,\,$ where$[.]$ denotes the greatest integer function, is discontinuous at
- AAll $x$
- BNo $x$
- ✓All integer points
- D$x$ which is not an integer
Since $g(x) = [x]$ is always discontinuous at all integral values of points.
Hence $f(x)$ is discontinuous for all integral points.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\left\{(\mathrm{x}, \mathrm{y}) \in \mathrm{R}^{2} | 4 \mathrm{x}^{2} \leq \mathrm{y} \leq 8 \mathrm{x}+12\right)$ is