MCQ
The function$f(x) = [x]\cos \left[ {\frac{{2x - 1}}{2}} \right]\pi ,\,$ where$[.]$ denotes the greatest integer function, is discontinuous at
  • A
    All $x$
  • B
    No $x$
  • All integer points
  • D
    $x$ which is not an integer

Answer

Correct option: C.
All integer points
c
(c) $f(x) = [x]\cos \,\left[ {\frac{{2x - 1}}{2}} \right]\,\pi $

Since $g(x) = [x]$ is always discontinuous at all integral values of points. 

Hence $f(x)$ is discontinuous for all integral points.

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