Question
The fundamental frequency of a closed pipe is 293Hz when the air in it is at a temperature of 20°C. What will be its fundamental frequency when the temperature changes to 22°C?

Answer

We know that the frequency = f, T = temperatures$\text{f}\propto\sqrt{\text{T}}$
So, $\frac{\text{f}_1}{\text{f}_2}=\frac{\sqrt{\text{T}_1}}{\sqrt{\text{T}}}$$\Rightarrow\frac{293}{\text{f}_2}=\frac{\sqrt{293}}{\sqrt{295}}$
$\Rightarrow\text{f}_2=\frac{293\times\sqrt{295}}{\sqrt{293}}=294$

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