MCQ
The general formula for monocarboxylic acids is
- A${C_n}{H_n}COOH$
- B${C_n}{H_{2n + 1}}COOH$
- C${C_n}{H_{2n}}{O_2}$
- ✓Both $(b)$ and $(c)$
✓
Answer
Correct option: D.
Both $(b)$ and $(c)$
d
(d) General formula of monocarboxylic acid is ${C_n}{H_{2n + 1}}COOH$ or ${C_n}{H_{2n}}{O_2}$.
(d) General formula of monocarboxylic acid is ${C_n}{H_{2n + 1}}COOH$ or ${C_n}{H_{2n}}{O_2}$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If $1$ molal solution of benzoic acid in benzene has a freezing point depression of $2.56\,^oC$.
$(K_f = 5.12\,^oC\,mol^{-1}\, kg)$ and boiling point elevation of $2.53\,^oC$ $(K_b = 2.53\,^oC\,mol^{-1}\,kg)$, then select the correct statement/s :
Statement $I :$ there is dimer formation when undergoing freezing.
→$(K_f = 5.12\,^oC\,mol^{-1}\, kg)$ and boiling point elevation of $2.53\,^oC$ $(K_b = 2.53\,^oC\,mol^{-1}\,kg)$, then select the correct statement/s :
Statement $I :$ there is dimer formation when undergoing freezing.
Statement $II :$ there is no change when undergoing boiling
Statement $III :$ reverse of $I$ and $II$
Statement $IV :$ dimer formation in freezing and boiling state
One mole of a compound $AB$ reacts with one mole of a compound $CD$ according to the equation $AB + CD$ $\rightleftharpoons$ $AD + CB$. When equilibrium had been established it was found that $\frac{3}{4}$mole each of reactant $AB$ and $CD$ had been converted to $AD$ and $CB$. There is no change in volume. The equilibrium constant for the reaction is
→What is the major product expected from the following reaction ?
→Where $D$ is an isotope of hydrogen
The correct order of increasing basic nature for the bases $N{H_3},\,C{H_3}N{H_2}$ and ${(C{H_3})_2}NH$ is
→If $x$ is specific resistance (in $S^{-1}\,cm$) of the electrolyte solution and $y$ is the molarity of the solution, then ${\Lambda _m}$ (in $S \,cm^2\, mol^{-1}$) is given by
→The isomeric alcohol which has a chiral carbon atom is
Molten sodium chloride conducts electricity due to the presence of
Zirconium phosphate $[Zr_3 (PO_ 4)_4]$ dissociates into three zirconium cations of charge $+ 4$ and four phosphate anions of charge $- 3$. If molar solubility of zirconium phosphate is denoted by $S$ and its solubility product by $K_{sp}$ then which of the following relationship between $S$ and $K_{sp}$ is correct?
→Which will not affect the degree of ionisation
The molality of the solution prepared by dissolving $125\, mL$ of pure methanol $(d = 0.8\, g\,mL^{-1})$ in $375\, g$ of ethanol is
→