The general solution of ^2 + 3 = 0 is - Vidyadip

MCQ

The general solution of ${\sin ^2}\theta \sec \theta + \sqrt 3 \tan \theta = 0$ is

A
$\theta = n\pi + {( - 1)^{n + 1}}\frac{\pi }{3},\theta = n\pi ,n \in Z$
✓
$\theta = n\pi ,n \in Z$
C
$\theta = n\pi + {( - 1)^{n + 1}}\frac{\pi }{3},n \in Z$
D
$\theta = \frac{{n\pi }}{2},n \in Z$

✓

Answer

Correct option: B.

$\theta = n\pi ,n \in Z$

b
(b) The given equation can be written as

$ \Rightarrow $$\frac{{{{\sin }^2}\theta }}{{\cos \theta }} + \sqrt 3 \tan \theta = 0$

$ \Rightarrow $ $\tan \theta \sin \theta + \sqrt 3 \tan \theta = 0$

$\tan \theta (\sin \theta + \sqrt 3 ) = 0$

$ \Rightarrow $ $\tan \theta = 0$

$ \Rightarrow $$\theta = n\pi ,\,n \in Z$.

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