MCQ
The general solution of $\sin x - \cos x = \sqrt 2 $, for any integer $n$ is
- A$n\pi $
- ✓$2n\pi + \frac{{3\pi }}{4}$
- C$2n\pi $
- D$(2n + 1)\,\pi $
$\Rightarrow \cos \left( {x + \frac{\pi }{4}} \right) = - 1$
==> $x + \frac{\pi }{4} = 2n\pi \pm \pi $
$\Rightarrow 2n\pi + \frac{{3\pi }}{4}{\rm{\,\,or\,\,}}\,\,2n\pi - \frac{{5\pi }}{4}$ .
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