MCQ
The general solution of the differential equation $\frac{{dy}}{{dx}} = \cot x\cot y$ is
  • A
    $\cos x = c\,\cos {\rm{ec}}y$
  • $\sin x = c\sec y$
  • C
    $\sin x = c\cos y$
  • D
    $\cos x = c\sin y$

Answer

Correct option: B.
$\sin x = c\sec y$
b
(b) $\frac{{dy}}{{dx}} = \cot x\cot y$ ==> $\int_{}^{} {\tan ydy = \int_{}^{} {\cot xdx} } $

==> $\log \sec y = \log \sin x + \log c$

==> $\sec y = c\sin x$or$c\sec y = \sin x$.

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