MCQ
The general solution of the trigonometric equation $\tan \theta = \cot \alpha $ is
  • $\theta = n\pi + \frac{\pi }{2} - \alpha $
  • B
    $\theta = n\pi - \frac{\pi }{2} + \alpha $
  • C
    $\theta = n\pi + \frac{\pi }{2} + \alpha $
  • D
    $\theta = n\pi - \frac{\pi }{2} - \alpha $

Answer

Correct option: A.
$\theta = n\pi + \frac{\pi }{2} - \alpha $
a
(a) $\tan \theta = \cot \alpha$

$\Rightarrow \tan \theta = \tan \left( {\frac{\pi }{2} - \alpha } \right)$

$ \Rightarrow $ $\theta = n\pi + \frac{\pi }{2} - \alpha $.

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