MCQ
The general solution of ${x^2}\frac{{dy}}{{dx}} = 2$ is
  • A
    $y = c + \frac{2}{x}$
  • $y = c - \frac{2}{x}$
  • C
    $y = 2cx$
  • D
    $y = c - \frac{3}{{{x^2}}}$

Answer

Correct option: B.
$y = c - \frac{2}{x}$
b
(b) $\frac{{dy}}{{dx}} = \frac{2}{{{x^2}}}$ ==> $dy = \frac{2}{{{x^2}}}dx$,

Now integrate it.

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