MCQ
The general value $\theta $ is obtained from the equation $\cos 2\theta = \sin \alpha ,$ is
  • A
    $2\theta = \frac{\pi }{2} - \alpha $
  • B
    $\theta = 2n\pi \pm \left( {\frac{\pi }{2} - \alpha } \right)$
  • C
    $\theta = \frac{{n\pi + {{( - 1)}^n}\alpha }}{2}$
  • $\theta = n\pi \pm \left( {\frac{\pi }{4} - \frac{\alpha }{2}} \right)$

Answer

Correct option: D.
$\theta = n\pi \pm \left( {\frac{\pi }{4} - \frac{\alpha }{2}} \right)$
d
(d) $\cos 2\theta = \cos \left( {\frac{\pi }{2} - \alpha } \right)$

$\Rightarrow 2\theta = 2n\pi \pm \left( {\frac{\pi }{2} - \alpha } \right)$

$ \Rightarrow $ $\theta = n\pi \pm \left( {\frac{\pi }{4} - \frac{\alpha }{2}} \right)$.

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