MCQ
The geometry of $XeOF_4$ by $VSEPR$ theory is
- Apentagonal planar
- Boctahedral
- ✓square pyramidal
- Dtrigonal bipyramidal
✓
Answer
Correct option: C.
square pyramidal
c
In $XeOF_4$, $Xe$ is $sp^3d^2$, hybridised having $6$ bond pairs and $1$ lone pair
In $XeOF_4$, $Xe$ is $sp^3d^2$, hybridised having $6$ bond pairs and $1$ lone pair
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following species work as proton donator and acceptor both?
Which of the following has been arranged in increasing order of size of the hybrid orbitals ?
Which of the following will have geometrical isomers
How many grams of $Ca{C_2}{O_4}$ will dissolve in distilled water to make one litre of saturated solution ? (Solubility product of $Ca{C_2}{O_4}$ is $2.5 \times {10^{ - 9}}\,mol{e^2}\,litr{e^{ - 2}}$ and its molecular weight is $128$)
→Select the incorrect statement
→$(a)$ $PCl_5$ form weak monobasic acid during hydrolysis
$(b)$ In $B_3N_3H_6$ nucleophile attack on $B-$ atom
$(c)$ $Al_2Cl_6$ is a polar and planar molecule
$(d)$ In $AlF_3$, hybridisation of $Al$ is $sp^2$
The number of $\sigma $ and $\pi $ bonds present in pent$-4-$ene, $1-$yne is
→An element whose $IUPAC$ name is ununtrium $(Uut)$ belongs to
→Assign $A, B, C, D$ from given type of reaction.
$F{e^{2 + }}\left( {aq.} \right) + C{r_2}O_7^{2 - } + {H^ + } \longrightarrow F{e^{3 + }}\left( {aq.} \right) + C{r^{3 + }}$
→In an atom, an electron is moving with a speed of $600 m / s$ with an accuracy of $0.005 \%$. Certainty with which the position of the electron can be located is $\left( h =6.6 \times 10^{-34} Js \right)$ ?
→Cyclopentene on treatment with alkaline $KMn{O_4}$ gives
→