Question
The given figure shows a rectangle $\text{ABDC}$ and a parallelogram $\text{ABEF};$ drawn on opposite sides of $AB.$Prove that$:(i)$ Quadrilateral $\text{CDEF}$ is a parallelogram Area of the quad. $\text{CDEF}= $Area of rect. $\text{ABDC} +$ Area of $\|gm. ABEF.$

Answer

After drawing the opposite sides of $AB$, we get

Since from the figure, we get $CD\|FE,$ therefore, $FC$ must parallel to $DE.$
Therefore it is proved that the quadrilateral $CDEF$ is a parallelogram.
The area of the parallelogram on the same base and between the same parallel lines is always equal and the area of the parallelogram is equal to the area of a rectangle on the same base and of the same altitude.
i.e, between the same parallel lines.
So Area of $\text{CDEF}=$ Area of $\text{ABDC} +$ Area of $\text{ABEF}$
Hence Proved

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