MCQ
The given pair are
- Aenantiomers
- Bdiastereomers
- Chomomenrs
- ✓constitutional isomer
✓
Answer
Correct option: D.
constitutional isomer
d
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,Br} \\
| \\
{\mathop C\limits_4 {H_3} - \mathop C\limits_3 {H_2} - \mathop C\limits_2 H - \mathop C\limits_1 {H_2} - Cl}
\end{array}}\limits_{2 - Bromo - 1 - chlorobu\tan e} $ $\mathop {\begin{array}{*{20}{c}}
{\,Br\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,} \\
{Cl - \mathop C\limits_1 {H_2} - \mathop C\limits_2 {H_2} - \mathop C\limits_3 H - \mathop C\limits_4 {H_3}}
\end{array}}\limits_{2 - Bromo - 1 - chlorobu\tan e} $
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,Br} \\
| \\
{\mathop C\limits_4 {H_3} - \mathop C\limits_3 {H_2} - \mathop C\limits_2 H - \mathop C\limits_1 {H_2} - Cl}
\end{array}}\limits_{2 - Bromo - 1 - chlorobu\tan e} $ $\mathop {\begin{array}{*{20}{c}}
{\,Br\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,} \\
{Cl - \mathop C\limits_1 {H_2} - \mathop C\limits_2 {H_2} - \mathop C\limits_3 H - \mathop C\limits_4 {H_3}}
\end{array}}\limits_{2 - Bromo - 1 - chlorobu\tan e} $
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