MCQ
The G.M. of the numbers $3,\,{3^2},\,{3^3},\,......,\,{3^n}$ is
- A${3^{2/n}}$
- B${3^{(n - 1)/2}}$
- C${3^{n/2}}$
- ✓${3^{(n + 1)/2}}$
$ = {({3^{1 + 2 + .......n}})^{1/n}}$
$ = {\left( {{3^{\frac{{n\,(n + 1)}}{2}}}} \right)^{1/n}}$
$ = {3^{\frac{{n + 1}}{2}}}$.
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