Question
The graph given below represents the linear equation $x + y = 0.$

Answer

If the given points $(-1, 1)$ and $(- 3, 3)$ lie on the linear equation $x + y = 0,$
then both points will satisfy the equation. So, at point $(-1, 1),$
we put $x = -1,$ and $y = 1$ in $LHS$ of the given equation,
we get $LHS = x + y = -1 + 1 = 0 = RHS$ Again,
at point $(-3, 3)$ put $x = -3$ and $y = 3$ in $LHS$ of the given equation,
we get, $LHS = x + y= -3 + 3 = 0 = RHS$
Hence, $(-1, 1)$ and $(-3, 3)$ both satisfy the given linear equation $x + y = 0.$

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