MCQ
The graph of the linear equation y = 3x passes through the point.
- A$(0,-\frac{2}{3})$
- B$(\frac{2}{3},2)$
- C$(,-\frac{2}{3},0)$
- D$(0,\frac{2}{3})$
✓
Answer
- $(\frac{2}{3},2)$
Solution:
$\text{y}=3\text{x}$
$\frac{\text{y}}{3}=\text{x}$
For $\text{x}=\frac{2}{3},$ the value of $\text{y}=3\times\frac{2}{3}=2$
So $(\frac{2}{3},2).$
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